Q6) If 60% of (p - q) = 40% of (p + q) and q is k percent of p, then find k? 1) 25 2) 30 3) 15 4) 20 Solution: 60% of (p - q) = 40% of (p + q) i.e. 3(p - q)/5 = 2(p + q)/5 On solving, p = 5q k = (q/p)100 = (q/5q)100 = 20 Hence, option 4. Q7) 25% of the residents of a village die because of flu and 40% of the remaining residents leave the village in panic. The population is then reduced to 7290. Find the original number of residents? 1) 12100 2) 9720 3) 20800 4) 16200 Solution: Let y be the original number of residents. A.T.Q. (75/100)(60/100)y = 7290 On solving, y = 16200 Hence, option 4. Q8) In a class of 250 students, 64% are boys. So, how many boys are there in the class? 1) 135 2) 160 3) 150 4) None of these Solution: Boys = (64/100)250 = 160 Hence, option 2. Q9) Price of tea increase of 60%. By what fraction must a household reduce it's consumption of tea so as not to increase it's expenditure? 1) 3/5 2) 2/5 3) 3/8 4) 7/12 Solution: Reduction in consumption = 60/(100 + 60) = 3/8 Hence, option 3. Q10) A student scores 26% marks in an exam and fails by 15 marks. Another student scores 39% marks in an exam and gets 24 marks more than required for passing. Find the maximum number of marks? 1) 400 2) 450 3) 300 4) None of these Solution: Let the passing marks be y. 0.26y + 15 = 0.39y - 24 On solving, y = 300 Hence, option 3. |